Math, asked by nsapana114, 12 days ago

sunyana borrowed a sum of Rs 25000 at 12% p.a. simple interest for 1 year 6 month and lent to bishwant at the same rate of compound interest compound half -yearly for the same interval of time​

Answers

Answered by ritaarjun335
4

Answer:

compound interest=1570₹ and amount=31270 Rs

Step-by-step explanation:

Principal=25,000

Rate=12%

Time=1 year 6 months =1 ½ years

because 6 months =1/2 of 12 months

at S.I

s.i =  \frac{prt}{100}  \\  \\  =  \frac{25000 \times 1  \frac{1}{2}  \: years  \times 12}{100}  \\  \\  \frac{25000 \times  \frac{3}{2} \times 12 }{100}  \\  \\  =  \frac{25000 \times 18}{100}  \\  \\  = 250 \times 18 = s.i = 4500

amount at simple interest =25000+4500=29500

for compound interest see the attachment

so Amount compounded half yearly at compound interest =31270

and compound interest =31270-29500

=1570

we have taken half of rate because it is compounded half yearly and when the year is half or in fraction we multiply that fraction with rate.

Attachments:
Answered by durgeshshrivastav205
4

Answer:

275.4

Step-by-step explanation:

given

p = Rs 25000

R = 12%

T= 1years 6month

= 1year + 6\12 years

= 1 + 1\2

= 3\2 years

Now

S. I. = PTR\100

= (25000 × 3\2×12) \100

= Rs. 4500

Again,

semi - Compound interest

C. I. = p[( 1 + R\200) ^2T -1 ]

= 25000[(1 + 12\200) ^2×3\2 - 1 ]

= 25000[(1 + 12\200) ^3 - 1 ]

= 25000[( 1.o6)^3 - 1 ]

= 25000[(1.191016- 1 ]

= 25000x 0.191016

= Rs. 4,775.4

so, the difference of = C. I - S. I

=Rs 4,775.4 - Rs. 4500

= Rs 275.4

thus, the profit is Rs 275.4.

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