Question

Super Question
The product of sides of the squares are shown in the
figure is 60. The sum of areas of them is 136 square
centimetres.​

Answer 1

Step-by-step explanation:

Answer 2

Given :- The product of sides of two squares is 60.The sum of areas of them is 136 square centimeters. Taking the length of large square as x centimeters and that of Small Square as y centimeters, then

a) What are the numbers x y and x² + y² ?

b) Find the numbers x + y and x – y ?

c) Find the sides of the squares ?

Solution :-

sides of squares are x cm and y cm respectively. where x > y .

So,

→ Product of sides = x * y = xy = 60 cm² (a) (Ans.)

→ Sum of areas of squares = x² + y² = 136 cm² (a) (Ans.)

Now,

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab

So,

→ (x + y)² = x² + y² + 2xy

→ (x + y)² = 136 + 2 * 60

→ (x + y)² = 136 + 120

→ (x + y)² = 256

→ (x + y) = ±16

since negative sum of sides not possible ,

→ (x + y) = 16 . (b) (Ans.)

and,

→ (x - y)² = x² + y² - 2xy

→ (x - y)² = 136 - 2 * 60

→ (x - y)² = 136 - 120

→ (x - y)² = 16

→ (x - y) = ± 4 .

since x > y .

→ (x - y) = 4 . (b) (Ans.)

therefore,

→ (x + y) + (x - y) = 16 + 4

→ 2x = 20

→ x = 10 . (c) (Ans.)

→ y = 10 - 4 = 6 . (c) (Ans.)

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