Question

SUPER URGENT!

Rectangle ABCD is graphed in the coordinate plain. The following are the vertices of the rectangle: A(-4,-2), B(-2,-2), C(-2,7) and D(-4,7).

What is the area of rectangle ABCD?

Answer 1

Answer:

$18 unit^2$

Step-by-step explanation:

First you need to find the length and breadth of the rectangle.

Here's a formula to find the length between two coordinates.

$\sqrt{(x2 - x1)^{2} + (y2 - y1)^2 }$

By graphing, you can find the which is the length and breadth sides of that rectangle.

BC and AD are the lengths of the rectangle and AB and CD are the breadths of that rectangle.

By this you can find the length and breadth of the rectangle.

Length   = 9 units

Breadth = 2 units

So area = 9 × 2 = 18 unit square

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