Question

superfast express covers 350 km in 3 hr 30 min what is the speed of the train​

Answer 1

$\large \sf given \:$

• Distance = 350 km
• Time = 3 Hours 30 min

$\large \sf \: to \: find$

• What is the speed of the train?

$\sf \large \:formula \: used$

$\qquad \boxed{ \frak\red{ speed = \frac{distance}{time} \:} }$

$\large \frak{solution}$

First we will convert time In minutes

$\sf \: = 3 Hours + 30 min \\ \\ \sf = \: 3 \times 60 + 30 \qquad \{1 \: hours: = 60 \: min \} \\ \\ \sf \: = 180 + 30 \\ \\ \sf \: = \frak{ \green{210 \: min}}$

$\sf \: Therefore \qquad\frak{ \qquad \boxed{ \frak\red{ speed = \frac{distance}{time} \:} }}$

$\implies \sf \qquad { \frak\red{ speed = \frac{distance}{time} \:} }$

$\implies \sf \quad \: speed = \cancel\frac{350}{210}$

$\sf \qquad \qquad \: speed = 1.6 km / hours \:$

Answer 2

$\sf{Given}$

$\sf{Distance = 350 \: km}$

$\sf{Time = 3 \: Hours \: 30 \: min}$

$\sf{We \: have \: to \: find \: the \: speed \: of \: train}$

$\sf{So , Let \: let \: us \: convert \: the \: time \: into \: minutes :-}$

$\sf{Solution :-}$

$\sf \: ⟹ \: 3 \: Hours + 30 \: min \\ \\ \sf ⟹ \: 3 \times 60 + 30 \qquad \\ \\ \sf \: ⟹ \: 180 + 30 \\ \\ \sf \: ⟹ { {210 \: min}}$

$\sf{Formula \: of \: distance \: is : }$

$\sf{Distance : \frac{speed}{time} }$

$\sf{Solution :-}$

$\sf⟹ distance = \frac{speed}{time}$

$\sf \: ⟹ \: speed = \cancel\frac{350}{210}$

$\sf⟹ speed = 1.6 \: km \: per \: hour$

$\underline{\underline{\sf{Hence, the \: speed \: is \: 1.6 km/hr.}}}$