Math, asked by alicedevadharshini2, 1 month ago

supplier A has 2%defects while supplier B has 5% defects .80%of the products are made using the parts from supplier A.Given a product is defective,what is the probability that it is made using parts from A?​

Answers

Answered by EswarJanjanam
0

Answer:

10/13

Step-by-step explanation:

Probability of getting a defective product from A is 2/100

Probability of getting a defective product from B is 5/100

Since, 80% of the products are from A, the probability of getting defective products from the A is (80/100)x(2/100)

Then the remaining 20% of the products are from B and the probability of getting defective products from B is (20/100)x(5/100)

The total probability of getting defective product is the sum of defective products from A and B

n(s) = [(80/100)x(2/100)]+[(20/100)x(5/100)] = 13/500

The probability of getting defective product from A is given by 2/100 = 1/50

Hence the required probability is

P(A) = (1/50)/(13/500) = 10/13

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