Question

supply the missing terms in each of the following sequence 16,24,32,40, __​

Answer 1

Answer:

48........Every number increases by 8

Answer 2

$Given \: sequence \: 16,24,32,40, _$

$i) a_{2} - a_{1} = 24 - 16 = 8$

$ii) a_{3} - a_{2} = 32 - 24 = 8$

$iii) a_{4} - a_{3} = 40 - 32 = 8$

$\blue{ a_{2} - a_{1} = a_{3} - a_{2} =a_{4} - a_{3} =8}$

$\therefore Given \: sequence \: is \: in \:A.P$

$Here, a = 16 , d = 8, \: n = 5$

$\boxed{\pink{ n^{th} \:term (a_{n}) = a + (n-1)d }}$

$a_{5} = 16 + (5 - 1) \times 8\\= 16 + 4\times 8 \\= 16 + 32 \\= 48$

Therefore.,

$\red{ Required \: missing \:term }\green { = 48 }$

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