Question

Suppose 10 coins are tossed. Find the probability of getting
i) exactly 2 heads
ii) at most 2 heads
iii) at least 2 heads

Answer 1

Answer:

Step-by-step explanation:

no of outcomes=20

(I)No. of favourable outcomes=2

P(getting exactly 2 heads)=2\20=1\10

(iii)No. of favourable outcomes=17

P( getting at most 2 heads)=17\20

(ii) No. of favourable outcomes=5

P(getting at least 2 heads)=5\20=1\4