Question

Suppose 25 gm of steam at 120°C is mixed with 25 g of ice at -30°C. What will be the final temperature?​

Answer 1

Answer:

-25 oc

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Answer 2

Explanation:

we know that

total heat loss(steam) = total heat gain(ice)

25×0.48(120-t) = 25× 0.5(t-(-30))

0.48(120-t) = 1/2(t+30)

0.96(120-t) = t+30

115.2-0.96t = t+30

115.2 - 30=t + 0.96t

85.2 = 1.96t

t = 43.46°C

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