Suppose 2kg of sugar contains 9×10power6 crystals. How many sugar crystals are there in 1)5kg of sugar? 2)1. 2kg of sugar?
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Let the weight of sugar be x =2kg and no. Of crystals be y =9×10^6.And let the unknown quantity be n.It is a direct propotion.
1) x ÷y =5÷n
=2÷9×10^2 =5÷n
=n =5×9×10^6 ÷ 2
=n = 450×10^5
=n =225×10^5
=n = 2.25 ×10^7 crystals
2) x÷y = 1.2÷n
=2÷9×10^6 = 1.2÷n
=n =1.2×9×10^6 ÷2
=n =0.6×9×10^6
=n =5.4 × 10 ^6 crystals
You can do this with the help of making tabel and then solving.
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