Question

Suppose 6g of H2 and 16 g of CH4 are in a 1-L box divided in half by a thin partition, each gas at the same initial pressure P in atm. Upon mixing the gases, find the total pressure?

Answer 1

n(H2)=1 and n(CH4) = 1

P(H2) = (1/(1+1))*P =P/2

P(H2) = P/2

P(CH4) = 1/(1+1)P = P/2

so

p(tot) = P