Math, asked by hussandeepsingh8760, 7 months ago

Suppose 81^x = 64. What is 27^{x+1}?

Answers

Answered by mahpiyush

0

Answer:

8*9*2√2*3

Step-by-step explanation:

81^x = 9^x * 9^x

so 9^x = √64 = 8

3^x = 2√2

27 ^ {x+1}= 9^x * 9 * 3^x * 3 = 8*9*2√2*3

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