Question

Suppose a 1000 kg was traveling at a speed of 10m/s. Now, this mass transfers all its energy to a mass of 10 kg. What will be the velocity of the 10 kg mass after being hit by it?​

Answer 1

Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

Answer 2

Answer:

Velocity of the 10 kg mass = 14 m/s.

Explanation:

Given:

Mass of the Body $= 10 kg.$

Height of the body $= 10 m.$

Acceleration due to gravity $= 9.8 m/s^{2} .$

Step 1

By using the formula of potential energy,

Potential Energy = mgh

$= 10 * 9.8 * 10 = 980 J.$

Now, By the law of the conservation of energy, the entire amount of energy in the system stays constant.

Kinetic Energy before the body reaches the ground exists equivalent to the Potential Energy at the height of $10 m.$

Kinetic Energy $= 980 J.$

Step 2

Kinetic Energy $= 980 J.$

Mass of the ball $= 10 kg.$

$K.E. = 1/2 *mv^{2}$

⇒ $980 = 1/2 *10*v^{2}$

⇒ $v^{2} = 980/5$

⇒ $v^{2} = 196$

⇒ $v = 14 m/s.$

Therefore, velocity = 14 m/s.

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