Suppose a 14-gram sample of iron is heated from 20.0°C to 25.0°C. The specific heat of iron is 0.11 cal/g°C. How much heat energy was absorbed by the iron?
a)38.5 cal
b)7.7 cal
c)636 cal
d)69.3 cal
Answers
Answered by
1
Answer:
2102.1cal
Explanation:
Q = msT
m= 14g
s=0.11cal/g/°C
T = 273(25-20) = 1365
Q= 14*0.11*1365
Q = 2102.1Cal
Answered by
16
Answer:
7.7
Explanation:
H=ms(change in temp.)
h= 14×5×0.11
h=7.7
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