Suppose a= [2 – 1] =[6-1) and (A+B)2 =A2+ B2, then determine the value of a and b. O a=1, b =4 O a=4,b=1 O a=0,b=4 O a=2, b=4
Answers
Answered by
0
Step-by-step explanation:
hlo mate here's your answer
Since (A) is the intermediate reactive species whose concentration is determined from equilibrium step.
Slow step is:
A +
B
2
AB+
B
(slow)
r = k[A]
[B
2
]
From equilibrium step
A
2
⇌
A+
A(fast)
k
eq
=
[A
2
]
[A]
2
∴
[A]=
(k
eq
[A
2
]
1/2
Substitute the value of [A] in equation (i),
r=
k.k
eq
1/2 [A
2
]
1/2
[B
2
]
Thus, order of reaction =
2
1
+
1=
1
2
1
I HOPE ITS HELP YOU MARK AS BRAINLIST
Answered by
18
Answer;
Given a= [2-1] and b=[6-1]
we need to find (a+b)^2=a^2+2ab+b^2
= (1)^2+2×1×5+(5)^2
=1+10+25=36
hope it helps you ✌️✅✅✅
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