Question

suppose a 3 digit number ABC is divisible by 3 prove that A B C + BCA + c a b is divisible by 9 ​

Answer 1

Answer:Answer Expert Verified

Divisibility of 3: sum of its digits is divisible by 3. Divisibility of 9: sum of its digits is divisible by 9. Let the 3 digit number abc be 123 which is divisible by 3. we have to prove that abc+bca+cab is divisible by 9

Step-by-step explanation:

Answer 2

Answer:

Divisibility of 3: sum of its digits is divisible by 3. Divisibility of 9: sum of its digits is divisible by 9. Let the 3 digit number abc be 123 which is divisible by 3. we have to prove that abc+bca+cab is divisible by 9

Step-by-step explanation:

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