Question

Suppose A and B are two events for which P(A)=0.8, P(B)= 0.9 and P(AB)=0.4. Find the following probabilities A. P(AB') B. P(AB)' C. P(A'B')

Answer 1

Answer:

P(A)=0.5 and P(AB)=0.8

When A and B are independent events,  

P(A∩B)=P(A)×P(B)  

⇒P(A)+P(B)−P(A∪B)=0.5×q

⇒0.5+q−0.8=0.5q

⇒0.5q=0.3

⇒q=0.6

When A and B are mutually exclusive events  

P(A∩B)=0  

P(A)+P(B)=P(A∪B)

0.5+p=0.8

⇒p=0.3

Hence the ratio of q and p is 2

Step-by-step explanation: