Question

Suppose A, B and C form a Dobereiner's triad. If
atomic mass of A and C is 46 u and 52 u, then the
atomic mass of middle element B should be​

Answer 1

Answer:

Atomic mass of B is 49....

Explanation:

Given that,

it is a dobereiner's triad....

Then, atomic mass of B=A+C/2

B=46+52/2

B=98/2

B=49

Hope it helps you frnd......

Answer 2

Answer:

49u

Explanation:

Dobereiner stated in his law of triads that the arithmetic mean of the atomic masses of the first and third element in a triad would be approximately equal to the atomic mass of the second element in that triad.

Accoring to the law

Atomic mass of middle element B should be​ arithmetic mean of the atomic masses of the first and third element  A and C

Atomic mass of A = 46u

Atomic mass of C=52u

Arithetic mean= Sum of observations/No of observations

                       = (46+52)/2

                       = 98/2

Atomic mass of B = 49u