Question

Suppose (a,b) is a solution to the system of equations ab = 5 and (a^2)b +ab^2 + a + b = 42. determine a^2 + b^2

Answer 1

Answer:

a²+b²=39

Step-by-step explanation:

ab = 5

so b=5/a

and (a^2)b +ab^2 + a + b = 42

ab*(a +b)+a+b=42

(a+b)(ab+1)=42

(a+b)(5+1)=42

a+b=7

a²+b²+2ab=49

a²+b²+2*5=49

a²+b²=49-10=39

a²+b²=39

Answer 2

Answer:

a² + b² = 39

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