Question

Suppose a bike with a rider on it having a total mass of 63 kg brakes and reduces its velocity from 8.5 m/s to 0 m/s in 3.0 second. What is the magnitude of the braking force?

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Answer 1

To Find :-

• The magnitude of the braking force.

Solution :-

Given,

• Mass (m) = 63 kg
• Initial velocity (u) = 8.5 ms-¹
• Final velocity (v) = 0 ms-¹
• Time (t) = 3.0 s

The net force acting on the body is equal to the rate of change of momentum of the object.

Mathematically,

$\red \bigstar \: \bold{F= \frac{ \Delta p}{ \Delta t} }$

°.° The change in momentum of the car is given by,

$\sf \longrightarrow \Delta p = mv - mu$

$\longrightarrow \bold {\Delta p =m(v - u)} \: \green \bigstar$

So, the net force acting on the car is given by,

$\purple \bigstar \: \bold{F= \frac{ m(v - u)}{ \Delta t} }$

[ Put the values ]

$\longrightarrow \sf \: F = \frac{63( 0 - 8.5)}{3.0}$

$\longrightarrow \sf \: F = \frac{63 \times - 8.5}{30}$

$\longrightarrow \sf \: F = \frac{ - 535.5}{3.0}$

$\longrightarrow \sf \: F =- 178.5 \: N \:\red \bigstar$

Therefore,

The magnitude of the braking force is -178.5 N.

Answer 2

Answer:

Explanation:

170