Question

Suppose a bike with a rider on it having a total mass of 63 kg brakes and reduces its velocity from 8.5 m/s to 0 m/s in 3.0 second. What is the magnitude of the braking force?

Can anyone solve this?​

Answer 1

Answer:

178.5N

Step-by-step explanation:

refer the attached image!!!

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Answer 2

Given -

• Mass(m) = 63kg

• Initial velocity(u) = 8.5m/s

• Final velocity (v) = 0m/s

• Time(t) = 3.0 sec

To find -

• Magnitude of the braking force.

Solution -

Here we are given with the initial and final velocity. But, momentum = m × v, But here we are given initial and final velocity so will find their difference, so it will becomes m(v-u)

So,

Momentum = m(v - u)

where,

m = mass

v = final velocity

u = initial velocity

On substituting the values -

Momentum = m(v - u)

Momentum = 63(0 - 8.5)

Momentum = -535.5

Now,

We need to find the magnitude of the force, so here we will find the magnitude of the foce by dividing momentum by time.

On substituting the values -

Force = $\sf\dfrac{Momentum}{Time}$

Force = $\sf\dfrac{-535.5}{3}$

Force = -178.5N

$\therefore$ the magnitude of the braking force is -178.5N

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