Question

suppose a black ball has been drawn fron one of the three bags the first containing three black balls and seven white, the second five black ball and three white,the third eight black balls and four white.what is the probability that it was drawnfrom the first bag​

Answer 1

Given, Total ball in 1st bag is 3(b)+7(w)=10balls

2nd, balls=5(b)+3(w)=8balls

3rd,balls=8(b)+4(w) =12 balls.

Total balls in three bags=10+8+12 =30 balls.

The probability of getting black ball from 1st bag= 3/30

=1/10.

Thank you!