Question

Suppose a boy first runs a distance of 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from the shop to reach back home from where he started


What will be the displacement of the boy?
(i) 200 m (ii) 0 m (iii) 150 m (iv) -200 m Find the average speed of the boy.

(i) 1 m/s (ii) 2 m/s (iii) 3 m/s (iv) none of these
c. Find the velocity of the boy.
(i) 10m/s (ii) 4m/s (iii) 0 m/s (iv) 2 m/s


please ASAP in 10 mins​

Answer 1

Given : the boy first runs a distance of 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from the shop to reach back home from where he started

To Find:

What will be the displacement of the boy?

(i) 200 m (ii) 0 m (iii) 150 m (iv) -200 m

Find the average speed of the boy.

(i) 1 m/s (ii) 2 m/s (iii) 3 m/s (iv) none of these

c. Find the velocity of the boy.

(i) 10m/s (ii) 4m/s (iii) 0 m/s (iv) 2 m/s

Solution:

Displacement = Final Position - Initial Position

as boy returns  back to original position

Hence Final Position - Initial Position = 0

=> Displacement =  0  m

velocity = Displacement / Time

=> Velocity = 0/(50 + 50)  = 0 m/s

Average Speed = Total Distance / Total Time

=>Average Speed = (100 + 100)/(50 + 50)

=> Average Speed = 2 m/s

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Answer 2

Answer:

2m/s

Explanation:

s=d/t

=100+100/50+50

=200/100

=2m/s