Chemistry, asked by akirahs87, 5 hours ago

Suppose a certain material has a specific heat of 0.829 J/g°C. If 6.33 kJ of heat is applied to 530.6 g of the material at 22.5°C, what is the final temperature in °C) of the material?

Answers

Answered by ansh33977

Explanation:

The specific heat capacity of a metal is given as 0.745 J/ degree Celcius.What mass of the metal must be heated to 95 degree Celcius in order to be used to warm 2.548 L of water from 18.1 degree Celcius to 22.5 degree Celcius ?

I'm so confused I don't even know where to start

I know that Q= m•s•delta T

I'm thinking to rearrange the equation to

m=q/s•Delta T

I don't know I think what's really throwing me off is the 95degree Celcius

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Suppose a certain material has a specific heat of 0.829 J/g°C. If 6.33 kJ of heat is applied to 530.6 g of the material at 22.5°C, what is the final temperature in °C) of the material?​

Answers

Suppose a certain material has a specific heat of 0.829 J/g°C. If 6.33 kJ of heat is applied to 530.6 g of the material at 22.5°C, what is the final temperature in °C) of the material?