Question

Suppose a charge + on Earth's surface
and another +q charge is placed on
the surface of the Moon. (a) Calculat
the value of q required to balance th
gravitational attraction between Ear
and Moon (b) Suppose the distance
between the Moon and Earth is halved

would the charge q change?​

Answer 1

Answer:

q≈+5.64*10^13C

Explanation:

F(gravitational)=

GMeMm/r^2

Me -mass of earth

Mm- mass of moon

r -distance between earth and moon

F=308.83*10^35 /r^2

Now,

F(electrostatic)=9*10^9*q^2 /r^2

But r is same

q=√34.315*10^26

q≈5.64*10^13C