Question

suppose a compound X is made up of two element A and B if the ratio by mass of a ratio B in a molecule of X is 14 ratio 3 then calculate the ratio by number of atom for the same​

Answer 1

Explanation:

Let x and y be the atomic weights of X and Y

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y=

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.1

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y=

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.05

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2y

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2ySubstituting for x in Equation (2)

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2ySubstituting for x in Equation (2)⇒3(100−2y)+2y=180

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2ySubstituting for x in Equation (2)⇒3(100−2y)+2y=180⇒300−6y+2y=180

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2ySubstituting for x in Equation (2)⇒3(100−2y)+2y=180⇒300−6y+2y=180⇒y=30

Let x and y be the atomic weights of X and YGiven 0.1 mole of XY 2 weighs 10g⇒x+2y= 0.110 =100⟶(1)0.05 mole of X 3 Y 2 weighs 9g⇒3x+2y= 0.059 =180⟶(2)(1)⇒x=100−2ySubstituting for x in Equation (2)⇒3(100−2y)+2y=180⇒300−6y+2y=180⇒y=30Hence x=100−2(30)=40

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