Question

Suppose a compound X is made up of two elements A and B. If the ratio by mass of A B in a molecule of X is 14:3, then calculate the ratio by number of atoms for the same. [Atomic mass of A = 14 u, B = 1 u]​

Answer 1

Answer:

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Answer 2

Answer:

The ratio of the atoms of elements A and B in a molecule X is $1:3$, and the molecule can be represented as $AB_{3}$.

Explanation:

Given,

A compound X is made up of two elements = A and B.

The atomic mass of A = $14u$ = $14g/mol$

The atomic mass of B = $1u$ = $1g/mol$

The ratio of the masses of A and B in a molecule X = $14:3$.

Now, we can say that,

• $\frac{A}{B} = \frac{14}{3}$

So,

The mass of A = $14g$

The mass of B = $3g$

The ratio of the atoms present in the molecule =?

Firstly, we have to calculate the number of moles of each element.

For element A,

• Number of moles of element A = $\frac{Given mass}{Molar mass}$ = $\frac{14}{14}$ = $1mol$

For element B,

• Number of moles of element B = $\frac{Given mass}{Molar mass}$ = $\frac{3}{1}$ = $3 mol$

Now, as we know,

• 1 mole = $6.022\times 10^{23} atoms$

Thus, for element A,

• 1 mole = $6.022\times 10^{23} atoms$

For element B,

• 3 mole = $3\times 6.022\times 10^{23} atoms$

Now, the ratio of the atoms of elements A and B:

• $\frac{Atoms of element A}{Atoms of element B}$ = $\frac{6.022\times 10^{23} atoms}{3\times6.022\times 10^{23} atoms}$ = $\frac{1}{3}$

Therefore, the ratio of the atoms of elements A and B in a molecule X is $1:3$, and the molecule can be represented as $AB_{3}$.