Question

Suppose a computer has 16-bit instructions. The instruction set consists of 32 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The first of these addresses must be a register, and the second must be memory. Expanding opcodes are not used. The machine has 16 registers. What is the maximum allowable size for memory?

Answer 1

Answer:

A digital computer has a memory unit with 24 bits per word. The instruction set consists of 199 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. [] How many bits are needed for the opcode? How many bits are left for the address part of the instruction? What is the maximum allowable size for memory? What is the largest signed...