Suppose a die is rolled. You are told that the number is even. What is the probability that it is 4 ?
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Answered by
2
here, favourable outcomes =4.
and total outcomes=6
@probability will be;
favourable outcomes /total no. of outcomes.
=4/6
=2/3...
hope you get the perfect answer with explanation...
and total outcomes=6
@probability will be;
favourable outcomes /total no. of outcomes.
=4/6
=2/3...
hope you get the perfect answer with explanation...
Answered by
7
Hey there!
When a die is rolled , There are three cases when the number on the top is a even number,
So, n ( S) =3
S = { 2 , 4 , 6 }
The probability that it is 4 , Let it be a event called " E "
E = { 4 }
n ( E) = 1 .
Probability that it is 4 = P ( E) = n( E) / n(S ) = 1/3 .
Therefore, The probability that when a dice is rolled, and even numbers is obtained, then probability that it will be 4 is 1/3
When a die is rolled , There are three cases when the number on the top is a even number,
So, n ( S) =3
S = { 2 , 4 , 6 }
The probability that it is 4 , Let it be a event called " E "
E = { 4 }
n ( E) = 1 .
Probability that it is 4 = P ( E) = n( E) / n(S ) = 1/3 .
Therefore, The probability that when a dice is rolled, and even numbers is obtained, then probability that it will be 4 is 1/3
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