Question

Suppose a gas expands by 500. mL (0.500 L) against a pressure of 1.20 atm and no heat is exchanged with the surroundings during the expansion. (a) How much work is done in the expansion? (b) What is the change in internal energy of the system?​

Answer 1

Answer:

Hey mate here is your solution.

Explanation:

First law of thermodynamics:

This law is based upon the conservation of energy,

The mathematical form of the first law of thermodynamics is:

ΔE= q+ w

Here

ΔE = Change in internal energy

q= Absorbed heat by the system

w= Work done on the system.

So,

ΔE= q− PΔV

ΔE= 400− 2× 3.4× 101.33 J

ΔE= −289 J