Suppose a gas sample contains 3 x 1023
molecules. Each 1/3rd of the molecules have speed
2 x 103 cm/s, 3 x 103 cm/s and 4 x 103 cm/s. The
rms speed (in cm/s) of gas sample will be
Answers
Answered by
6
Answer:
Out of 6×10
23
molecules, 2×10
23
molecules have rms speed 10
4
cm/s, 2×10
23
molecules have rms speed 2×10
4
cm/s and 2×10
23
molecules have rms speed 3×10
4
cm/s.
The rms speed of gas sample can be calculated as,
v
rms
=
6×10
23
[2×10
23
×(10
4
)
2
]+[2×10
23
×(2×10
4
)
2
]+[2×10
23
×(3×10
4
)
2
]
v
rms
=
3
14×10
8
=2.16×10
4
cm/s
Answered by
1
Answer:
Correct answer is 2.16*10^4 cm/s
Explanation:
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