Question

Suppose a hammer of 1 kg falls freely on a wooden block. If it falls from a height of 1 m how much kinetic energy will it have just before hitting the ground?

Answer 1

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Given :-

U = 0

H = 1 m

A = g = 9.8 m/${s}^{2}$

V = ?

Using ;

${V}^{2} - {U}^{2} = 2as$

${V}^{2} - {U}^{2} = 2gh$

${V}^{2} = 2\:×\:9.8×\:1$

${V}^{2} =\: 19.6$

So ,

E(k) = $\frac{1}{2} \: m {v}^{2}$

=》 $\frac{1}{2} \times 1 \times 19.6$

=》 $9.8 \: j$

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Hope this helps. . . . . . ☺☺

Answer 2

firstly we have to find the velocity by using the formula V square is equals to U square + 2 g h .
and then we have to put the value of V in the formula kinetic energy is equals to half MV square .




hope it helps.....☺☺☺
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