Suppose a pendulum moves from A to B and from B to A than from A to C and back to its mean position A. Calculate distance and displacement
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distance=2ab+2ac
displacement=0
displacement=0
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displacement---- 0 as it comes back to is mean position. A IS INITIAL POINT , THEN IT GOES TO B , THE FINAL POINT IS A
SO S-> = INITIAL POINT - FINAL POINT
=A-A
= 0
same in a to c then c to a
S->= initial point- final point
= A-A
= 0
distance= speed*time
distance= 2ac+2ab
This depends on the question.....
First of all u find A TO B
THEN A TO C....
PLZ MARK IT AS BRAINLIEST ANSWER...AND CLICK ON THANKS BUTTON
SO S-> = INITIAL POINT - FINAL POINT
=A-A
= 0
same in a to c then c to a
S->= initial point- final point
= A-A
= 0
distance= speed*time
distance= 2ac+2ab
This depends on the question.....
First of all u find A TO B
THEN A TO C....
PLZ MARK IT AS BRAINLIEST ANSWER...AND CLICK ON THANKS BUTTON
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