Math, asked by kavi4016, 1 year ago

Suppose a population A has 100 observations 101, 102, .,.,200 and another population B has 100 observations 151, 152, ..,, 250.

Answers

Answered by Anonymous
15

Answer:

1

Step-by-step explanation:

Number of populations = 2 = A and B. (Given)

Observations of population A = 100 -- 101, 102 .. 200 (Given)

Observations of population B = 100 -- 151, 152 .. 250 (Given)

Formula to calculate = ∞² = ∈d²i/n

where the deviation is taken from mean.

Since, variance is independent of change of its origin. Therefore, the variance of observations 101 , 102, ... ,200 will be the same as variance of 151, 152, ,.., 250. Since A and B both have 100 consecutive integers, therefore both will have same standard deviation and hence the variance -

Va = Vb

= Va/Vb

= 1

Answered by samikshakawale9359
0

formula:for Standard derivation of n natural number

 \sqrt{n {}^{2}  - 1 \div 12}

step 1: calculate SD of first 200numbers

calculate SD of first 100 numbers

step2: calculate difference between above two SDwhich is a sd of numbers from 101 to 200

as like calculate SD for numbers 151 to 250

formula: mean = sum of numbers total number

natural number= n(n-1)÷2

step 1: calculate sum of 1 St 200 natural no.

calculate sum of 1St 100 natural no.

step 2: calculate difference of above sum which is sum of no.from 101 to 200

as like calculate the sum from 151to250

formula: variance: SD mean

final answer=1

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