Question

suppose a position of a particle as a function of time is given as x = 5t2 + 4t + 3 find the velocity of the particle at t = 2s​

Answer 1

Answer:

The displacement is given as x=5t2+4t+3

⇒x−3=5t2+4t

assuming x−3=s,

s=4t+2110t2

comparing this with s=ut+21at2

we get u=4m/s and a=10m/s2

so velocity at t=2sec is v=u+at=4+10×2=24m/s