Physics, asked by Kristen6657, 11 months ago

Suppose a __ ___Ra nucleus at rest and in ground state undergoes __-decay to a __ ___Rn nucleus in its excited state. The kinetic energy of the emitted __ particle is found to be 4.44 MeV. __ ___Rn nucleus then goes to its ground state by __-decay. The energy of the emitted __ photon is _____keV.
[Given: atomic mass of __ ___Ra =226.005 u,atomic mass of __ ___Rn = 222.000 u , atomic mass of __ particle= 4.000 u, 1 u = 931 MeV/c_, c is speed of the light]

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Answered by Anonymous
0

Answer:

Suppose a

88

226

Ra nucleus at rest and in ground state undergoes α-decay to a

88

222

Rn nucleus in its excited state. The kinetic energy of the emitted α particle is found to be 4.44MeV.

86

222

Rn nucleus then goes to its ground state by γ-decay. The energy of the emitted γ photon is ____ keV..

[Given : atomic mass of

88

226

Ra=226.005u, atomic mass of

88

222

Rn=222.000u, atomic mass of α particle = 4.000u,1u=931MeV/c

2

,c is speed of light]

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