Suppose a squirrel is moving at a steady speed from the base of a tree towards some nuts. It then stays in the same position for a while, eating the nuts, before returning to the tree at the same speed. A graph can be plotted with distance on the y-axis and the time on x-axis. (4) Observe the graph carefully and answer the following questions. (i) Which part of the graph shows the squirrel moving away from the tree? (ii) Name the point on the graph which is 6 m away from the base of the tree. (iii) Which part of the graph shows that the squirrel is not moving? (iv) Which part of the graph shows that the squirrel is returning to the tree? (v) Calculate the speed of the squirrel from the graph during its journey
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Answer:
Here is your answer mate!
Explanation:
(I) Part AB
(II) Part B
(III) Part BC
(IV) Part CD
(V) Total distance travelled is : 6+6=12m
T= 11sec
Hope you understood!
Answered by
16
The answers to the questions are as follows:
i) Part AB of the graph shows the squirrel moving away from the tree
- The slope of the segment is positive. Since the slope of a distance-time graph gives the speed of the squirrel, hence the squirrel is moving towards the nut away from the tree in segment AB.
(ii) Point B is 6 m away from the base of the tree.
- If we draw a straight line from point B to the y-axis, we can conclude that point B is 6 m away from the tree.
(iii) Part BC shows that the squirrel is not moving.
- The distance-time graph is a straight line in the part BC. Thus the slope = 0 and hence the speed of the squirrel is also zero. This proves that the squirrel is at rest.
(iv) Part CD shows that the squirrel is returning to the tree.
- The slope in part CD is negative. Thus the speed is negative.
(v) The speed of the squirrel is 1.09m/s.
- Total distance travelled = 6m + 6m = 12 m
- Time taken = 11s
- Speed = distance / time = 12 / 11 = 1.09m/s
(The graph from the question is attached below)
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