Question

Suppose a telephone company what's to position a relay tower at p between a and b is such a way that the distance of the tower from B is twice its distance from a if p lies on a b it will divide a b in the ratio 1 ratio 2 . If we take a is the origin and one kilometre is one unit on both the axes the coordinates of B will be 36,15 in order to know the position of the tower weavers to do the coordinates of p how do we find the coordinates

Answer 1

Answer:

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Answer 2

Coordinates of p = (12 , 5)

Step-by-step explanation:

a = (0 , 0)

b = (36 , 15)

pb = 2ap

=> ap : pb = 1 : 2

Coordinate of p  =  (1 * 36 + 0)/(1 + 2) , ( 1 * 15  + 0)/(1 + 2)

= 36/3 , 15/3

= 12 , 5

Coordinates of p = (12 , 5)

Distance of tower from a = √12² + 5² = 13 km

Distance of Tower from b = 2 * 13 = 26 km

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