suppose ABC is a triangle in which BE AND CF are respectively the perpendicular 's to the sides AC and AB . If BE= CF , prove that triangle ABC is isoscles
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area of triangle ABC = 1/2*AB*CF, with AB as base
area of triangle ABC= 1/2*AC*BE
1/2*AB*CF = 1/2*AC*BE
since BE =CF
AB=AC
ABC IS an isosceles triangle
area of triangle ABC= 1/2*AC*BE
1/2*AB*CF = 1/2*AC*BE
since BE =CF
AB=AC
ABC IS an isosceles triangle
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