Question

Suppose all the electrons of 100 g water are lumped together to form a negatively-charged particle and all the nuclei are lumped together to form a positively-charged particle. If these two particles are placed 10.0 cm away from each other, find the force of attraction between them. Compare it with your weight.

Answer 1

Explanation:

nuclei are lumped what is the meaning of the towards

Answer 2

Explanation:

Step 1:

Molecular water mass= 18 g

So, atoms in H2O, 18 g = number of Avogadro

                                                   $=6.023 \times[10] \wedge 23$

Amount of electrons per one  H2O atom = $(2 \times 1)+8=10$

Total electrons in 6.023 × 1023 atoms of H2O= $6.023 \times[10] \wedge 24$

i.e. ,total amount of electrons in 18 g of H2O = $6.023 \times[10] \wedge 24$

The amount of electrons in 100 g of H2O = $(6.023 \times[10] \times 24) / 18 \times 100$

                                                         $=3.34 \times[10] \wedge 25$

Step 2:

Net charge = $3.34 \times$$[10]^{\wedge} 25 \times\left(-1.6 \times[10]^{\wedge}(-19)\right)$

                   $=-5.34 \times[10] \wedge 6 \mathrm{C}$

q_1= -5.34 × [10]^6   C  

q_2  = +5.34 × [10]^6  C  

q1 is net electrons  charge in 100 gm of water,  

q2 is  net protons charge in 100 gm of water,  

r = 10 cm = 0.1 m

Step 3:

Electrostatic force by Coulomb's Law,          

$F=1 /\left(4 \pi \varepsilon_{-} O\right)\left(q_{-} 1 q_{-} 2\right) / r^{\wedge} 2$

 =9×[10]^9×(5.34×[10]^6×5.34×[10]^6)/[10]^(-2) =2.56×[10]^24  N

In fact, the force will be attractive.  

The result shows that the electrostatic force is greater than the gravitational force between any one of us and the planet (weight = gravitational force between us and earth).