Suppose an astronaut lands on the moon and drops an object from the height of 7.35m from the surface. How much time will it take to reach the moon's surface?
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Answers
Answered by
6
Answer:
height = 4.97 acceleration due to gravity(g) = 1.6m/s2 (approx) initial velocity (u) = 0m/s using formula -s = ut + 1/2 at2 4.97 = (0)(t) + 1/2 * 1.6 t2 = 0 + 0.8t2 t2 = 6.21 t = 2.49seconds
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Answered by
10
Answer:
:using formula
S=ut+1/2at2
U=0,
So.
4.97=0+1/2*10/6(gravity of moon)*t^2
(4.97*2*10)/6=t^2
5.964=t^2
2.44=t
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