Suppose an object of mass, mis moving along
a straight line with an initial velocity, u. It is
uniformly accelerated to velocity, v in time, t
by the application of a constant force, F
throughout the time, t. The initial and final
momentum of the object will be, p. = mu and
P2 = mu respectively.
Answers
Answer:
The initial velocity of the body is given as u .
The final velocity of the body is given as v.
The mass of the body is given as m .
The body is acted upon by a constant non zero force F.
The momentum of a body is defined as the product of mass with velocity.
Mathematically momentum p = mv.
The initial momentum of the body p = m×u
The final momentum of the body p' = m×v
The change in momentum dp = p' - p
= mv - mu
= m ( v- u)
The time taken by the body is t .
From Newton's second law, we know that rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.
Mathematically it can be written as
dp/dt=F
⇒ m(v-u)/t= F
therefore, F= m(v-u) /t.
This is the required expression among F, u, v and t respectively.
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Answer:
Explanation:
The initial velocity of the body is given as u .
The final velocity of the body is given as v.
The mass of the body is given as m .
The body is acted upon by a constant non zero force F.
The momentum of a body is defined as the product of mass with velocity.
Mathematically momentum p = mv.
The initial momentum of the body p = m×u
The final momentum of the body p' = m×v
The change in momentum dp = p' - p
= mv - mu
= m ( v- u)
The time taken by the body is t .
From Newton's second law, we know that rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.
Mathematically it can be written as
⇒
This is the required expression among F, u, v and t respectively.