Chemistry, asked by Anonymous, 1 year ago

Suppose chemists would have chosen 10^20 as the number of particles in a mole, the mass of 1 mole of oxygen gas would be what? And how?


Ramos39: 32grams

Answers

Answered by TPS
123
1 mole has 6.022 × 10^23 particles in it.

mass of 1 mole of oxygen = 32g

or mass of 6.022 × 10^23 oxygen molecule = 32g

mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23) = 32/6.022 × 10^(-23) g = 5.314 × 10^(-23) g

mass of 10^20 oxygen molecules = 5.314 × 10^(-23) × 10^20 = 5.314×10^(-3) g

So mass of 1 mole of oxygen will be 5.314×10^(-3) g if we take 10^20 as the number of particles in a mole

TPS: its incomplete
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Anonymous: I appreciate your efforts but the answer comes out to be 5.32×10^-3 g and I just don't know how it came
TPS: sorry. molar mass of O2 is 32. i took 16.
Anonymous: It's ok. Thank you so much for the answer :)
TPS: okay. done now...
Answered by smartyAnushka
81
Solutions :-


We know that

1 mole = 6.022 × 10^23 particles .

Mass of 1 mole of oxygen = 32g

Mass of 1 mole of partcle =
Mass of 6.022 × 10^23 oxygen molecule = 32g

Now ,


Mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23)

=> 32/6.022 × 10^-23g
=> 5.314 × 10^-23g

Mass of 10^20 oxygen molecules = Mass of 1 oxygen molecule× 10^20

=>5.314 × 10^(-23) × 10^20 =>5.314×10^-3 g✔



Thanks

@Anushka

Anonymous: thank you so much!
smartyAnushka: its ok
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