Suppose chemists would have chosen 10^20 as the number of particles in a mole, the mass of 1 mole of oxygen gas would be what? And how?
Ramos39:
32grams
Answers
Answered by
123
1 mole has 6.022 × 10^23 particles in it.
mass of 1 mole of oxygen = 32g
or mass of 6.022 × 10^23 oxygen molecule = 32g
mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23) = 32/6.022 × 10^(-23) g = 5.314 × 10^(-23) g
mass of 10^20 oxygen molecules = 5.314 × 10^(-23) × 10^20 = 5.314×10^(-3) g
So mass of 1 mole of oxygen will be 5.314×10^(-3) g if we take 10^20 as the number of particles in a mole
mass of 1 mole of oxygen = 32g
or mass of 6.022 × 10^23 oxygen molecule = 32g
mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23) = 32/6.022 × 10^(-23) g = 5.314 × 10^(-23) g
mass of 10^20 oxygen molecules = 5.314 × 10^(-23) × 10^20 = 5.314×10^(-3) g
So mass of 1 mole of oxygen will be 5.314×10^(-3) g if we take 10^20 as the number of particles in a mole
Answered by
81
Solutions :-
We know that
1 mole = 6.022 × 10^23 particles .
Mass of 1 mole of oxygen = 32g
Mass of 1 mole of partcle =
Mass of 6.022 × 10^23 oxygen molecule = 32g
Now ,
Mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23)
=> 32/6.022 × 10^-23g
=> 5.314 × 10^-23g
Mass of 10^20 oxygen molecules = Mass of 1 oxygen molecule× 10^20
=>5.314 × 10^(-23) × 10^20 =>5.314×10^-3 g✔
Thanks
@Anushka
We know that
1 mole = 6.022 × 10^23 particles .
Mass of 1 mole of oxygen = 32g
Mass of 1 mole of partcle =
Mass of 6.022 × 10^23 oxygen molecule = 32g
Now ,
Mass of 1 oxygen molecule = 32 ÷ (6.022 × 10^23)
=> 32/6.022 × 10^-23g
=> 5.314 × 10^-23g
Mass of 10^20 oxygen molecules = Mass of 1 oxygen molecule× 10^20
=>5.314 × 10^(-23) × 10^20 =>5.314×10^-3 g✔
Thanks
@Anushka
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