Science, asked by afrinperween62, 3 months ago


Suppose drinking water contains 1.0 mg/L of toluene
and 0.01 mg/L of tetra- Chloroethylene (C2014). A 70kg
adult drinks 21 per day of this water for ten years.
The calculated average daily dose (ADD)for toluene
0.034 mg/kg day. Assume Reference dose (RFD) for
toluene as 0 .196 mg/kg day.
mg/kg day. The hazard quotient
(HQ) for toluene is_________?​

Answers

Answered by Anonymous
7

Answer:

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answer

Explanation:

answers

Answered by HrishikeshSangha
0

The hazard quotient (HQ) for toluene is 0.173.

The hazard quotient (HQ) for toluene can be calculated using the formula:

HQ = (ADD) / (RFD)

Here, ADD = 0.034 mg/kg day and RFD = 0.196 mg/kg day.

So, the HQ for toluene is:

HQ = 0.034 mg/kg day / 0.196 mg/kg day

HQ = 0.173

Since the HQ for toluene is less than 1, it suggests that exposure to toluene is not likely to cause adverse health effects in the individual. However, it is important to note that this calculation only takes into account the exposure to toluene and not the exposure to tetra-chloroethylene, which may have its own separate health effects.

For more reference visit,

https://brainly.in/question/37661675?referrer=searchResults

https://brainly.in/question/14017606?referrer=searchResults

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