Question

Suppose Earth's orbital motion around the Sun is suddenly stopped.What time the Earth will take to fall into the sun?

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Answer 1

Explanation:

Kepler's law applies to planetary orbits, whether they be of circular, or elliptical shape. It says that

$\frac{t \frac{2}{2} }{t \frac{1}{2} } = \frac{r \frac{2}{3} }{r \frac{1}{3} }$

where T is the period of an orbit and R is its semi-major axis. The semi-major axis is the average of the planet's maximum and minimum distances from the sun.

Let the earth's mean radius be R1

..This straight fall can be considered 1/2 of a degenerate elliptical orbit with major axis equal to R1

. Its semi-major axis is

$\frac{r1}{2}$

(the average of R1 and zero). Its period will be designated T^2

So:

$\frac{t \frac{2}{2} }{t \frac{2}{1} } = \frac{( \frac{r1}{2} )^{3} }{r \frac{3}{1} } = ( \frac{1}{3} ) ^{3}$

And therefore,

=0.353 year, and the time to fall into the sun is the time to fall into the sun is ,64.52 days

Answer 2

Answer:

the time to fall into the is 6.25 and the earth will take fall that ways

Explanation:

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