Question

suppose f(a b)=a'+b. simplified expression for function f(f(x+y y) z) is

Answer 1

Answer:

x.y'+z

Explanation:

f(a b )=a'+b  then

f(x+y y)=(x+y)'+y

           =(x'.y')+y       bcoz:     (a+b)'=  a'.b'  

             =x'+y.y+y'

             =x'+y.1               bcoz  x.1=x

             =x'+y

f((x'+y) z)=((x'+y)' + z=

               x'' .y'+z=             bcoz,   x''=x

               x.y'+z