Suppose f(x) = and g(x) is an anti derivative of f(x) .
If g(5) = 7, then find the value of g(1) .
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= f (x) = x²g(x),g(1) =6 and g '(1)=3
= f ' (x) =2xg(x) + x²g'(x)
= f (1) =2(1)g (1)+(1)² g(1)
= f (1) =2(1) (6) + (1) (3) =12+3=15
= f (1) = 15
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