Math, asked by biraj7781, 6 months ago

Suppose gg is a continuous real-valued function such that 3x5+96=∫g(t)dt3x5+96=∫g(t)dt ( the limit of the integeral from cc to xx ) for each x∈Rx∈R . Where cc is a constant. What is the value of cc ?​

Answers

Answered by rashich1219
9

Given:

g is a continuous real-valued function such that 3x^5+96=∫g(t) dt for each  x∈ R and c is a constant.

To Find:

What is the value of c ?​

Solution:

Since, it is given that-

3x^5+96=\int {g(t)} \, dt                  .......(1)

Also, we know that , general formula of integration for any function f(x) is

\int{f(x)} \, dx = g(x) +c

therefore, g(x)+c=\int {f(x)} \, dx .......(2)

On comparing equation with general formula of integration, we get

c=96.

Hence, value of c is 96.

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