Question

Suppose height of a right angled triangle is 1 less than two times its base. It's hypotenuse is 7 less than 3 times
its base. Find all sides of right angled triangle.
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Answer 1

Answer:

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Step-by-step explanation:

Let,

height=2b-1

hyp.=3b-7

base=b

::b^2+b^2=hyp.^2

( by Pythagorus theorem)

(2b-1)^2+^2=(3b-7)^2

=4b^2+1-4b+b^2=9b^2-42b+49

=9b^2-42b+49=5b^2-4b+1

::we get ,

=4b^2-38b+48=0

::divide all terms by 2,we get

2b^2-19b+24=0

2^2-16-3+24

2(-8)-3(-8)=0

::base=8

{height=2(8)-1=16-1=15}

{hyp.=3(8)-7=24-7=17