Math, asked by sket, 10 months ago

Suppose in box ther are 20 red,30black,40blue amd 50white ball.what is the minimum number of balls to be drawn without replacemen,so that your certain about getting 4 red,5 black,6 blue and 7 white balls?

Answers

Answered by rajdigitalvja
2

Answer:

R = 28 = 28% chance

G = 20 = 20% chance

Y = 19 = 19% chance

B = 13 = 13% chance

W = 11 = 11% chance

B2 = 9 = 9% chance

Total number of balls is = 100

Requirement Draw at least 15 balls of a single color

Probability question

Though question is what is the minimum number of balls that must be drawn without replacement to guarantee at least 15 balls of a single colour.

Ok so any Ball that there is less than 15 of needs to be put in another category

so we get a new table

R = 28 = 28% chance

G = 20 = 20% chance

Y = 19 = 19% chance

BWB2 = 33 = 33% chance

So there is a 33% of drawing a ball that gets us no closer to … (more)

Step-by-step explanation:

Answered by anshuaabha1234
4

Answer:

124

Step-by-step explanation:

suppose he is unluckiest person he will get all these at end

that means all the first 50 white comes, then all 40 he get blue ,total 90 balls that is even after taking all the 90 balls he   did not get all the colours

then he took 30 balls all the balls came out black,

total became 90+30=120

after getting 120 balls he only left with red balls

now he only needs 4 red balls so all the conditions satisfied now

120+4=124 balls  

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