Question

Suppose m and n are disint integers . Can three to the power m multiply 2 to the power n divided by 2 to the power multiply 3 to the

Answer 1

Step-by-step explanation:

Given that:

We divide the two expressions

[3^m × 2^n] /2^m × 3^n

✔️ Since the denominator and numerator have common base so their powers can be subtracted

= (3/2)^m-n

✔️ Since m and n are two distinct integers so the power can never become 0 and hence the fraction can never an integer.

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Answer 2

Hi dear!♥️

Please refer to attachment :)